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Pipe A can fill a tank in 12 hours and p...

Pipe A can fill a tank in 12 hours and pipe B can empty the tank in 18 hours. Both pipes are opened at 6 a.m. and after some time pipe B is closed and the tank is full at 8 p.m. At what time was the pipe B closed ?

A

10 a.m.

B

8 a.m.

C

9 a.m.

D

11 a.m.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to analyze the information given and set up an equation based on the rates of work for both pipes. ### Step 1: Determine the rates of work for both pipes. - Pipe A can fill the tank in 12 hours. Therefore, its rate of work is: \[ \text{Rate of Pipe A} = \frac{1}{12} \text{ tank/hour} \] - Pipe B can empty the tank in 18 hours. Therefore, its rate of work is: \[ \text{Rate of Pipe B} = \frac{1}{18} \text{ tank/hour} \] ### Step 2: Calculate the total time taken to fill the tank. - The pipes are opened at 6 a.m. and the tank is full at 8 p.m. This means the total time taken to fill the tank is: \[ 8 \text{ p.m.} - 6 \text{ a.m.} = 14 \text{ hours} \] ### Step 3: Let \( x \) be the time (in hours) that Pipe B is open. - Pipe A is open for the entire 14 hours. - Pipe B is open for \( x \) hours. ### Step 4: Set up the equation based on the work done. - The work done by Pipe A in 14 hours is: \[ \text{Work by Pipe A} = 14 \times \frac{1}{12} = \frac{14}{12} = \frac{7}{6} \text{ tanks} \] - The work done by Pipe B in \( x \) hours is: \[ \text{Work by Pipe B} = x \times \frac{1}{18} = \frac{x}{18} \text{ tanks} \] - Since the tank is full, the total work done is equal to 1 tank. Therefore, we can set up the equation: \[ \frac{7}{6} - \frac{x}{18} = 1 \] ### Step 5: Solve the equation for \( x \). - Rearranging the equation gives: \[ \frac{7}{6} - 1 = \frac{x}{18} \] \[ \frac{1}{6} = \frac{x}{18} \] - Cross-multiplying gives: \[ 1 \times 18 = 6 \times x \] \[ 18 = 6x \] \[ x = \frac{18}{6} = 3 \] ### Step 6: Determine the time when Pipe B was closed. - Since Pipe B was open for \( x = 3 \) hours and it was opened at 6 a.m., it was closed at: \[ 6 \text{ a.m.} + 3 \text{ hours} = 9 \text{ a.m.} \] ### Final Answer: Pipe B was closed at **9 a.m.**. ---

To solve the problem step by step, we need to analyze the information given and set up an equation based on the rates of work for both pipes. ### Step 1: Determine the rates of work for both pipes. - Pipe A can fill the tank in 12 hours. Therefore, its rate of work is: \[ \text{Rate of Pipe A} = \frac{1}{12} \text{ tank/hour} \] - Pipe B can empty the tank in 18 hours. Therefore, its rate of work is: ...
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Knowledge Check

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