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Find the area lying in the first quadran...

Find the area lying in the first quadrant and bounded by the curve `y=x^3` and the line `y=4xdot`

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The correct Answer is:
4 sq. units
`"The line "y=4x" meets "y=x^(3)" at "4x=x^(3)`.
`therefore" "x=0, 2,-2rArry=0,8,-8`
`rArr" "A=int_(0)^(2)(4x-x^(3))=(2x^(2)-(x^(4))/(4))_(0)^(2)=4` sq. units
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