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A hollow hemispherical bowl of thickness...

A hollow hemispherical bowl of thickness 1 cm has an inner radius of 6 cm. Find the volume of metal required to make the bowl.

Text Solution

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Inner radius, r = 6 cm
thickness, t = 1 cm
` :. " Outer radius, " R=r+t=6+1=7 cm`
` :. " Volume of steel required "=(2)/(3)pi R^(3)-(2)/(3) pi r^(3)`
`=(2)/(3) xx (22)/(7) xx 7^(3)-(2)/(3) xx (22)/(7) xx 6^(3)=(44)/(21) (7^(3) -6^(3))`
`=(44)/(21)(343-216)=(44)/(21)xx 127=(5588)/(21) cm^(2)`.
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