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If x^(2) - y^(2) = 1, (x gt y) then find...

If `x^(2) - y^(2) = 1, (x gt y)` then find the value of `log_(x-y) (x+y)`

A

-2

B

2

C

-1

D

1

Text Solution

Verified by Experts

The correct Answer is:
C
Given ` x^(2) - y^(2) =1`
Applying log on both the sides, we get `log(x^(2) -y^(2))`
= log 1
` Rightarrow log(x+y) (x-y) =0`
log(x+y) + log (x-y) =0
log (x + y) = -log (x-y)
` (log (x+y))/(log (x-y))= -1`
` Rightarrow log_(x-y) (x+y) = -1`
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