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If 15 mg of N(2)O(3) is added to 4.82 x...

If 15 mg of `N_(2)O_(3)` is added to `4.82 xx 10^(20)` molecules of `N_(2)O_(3)`, the total volume occupied by the gas at STP is

A

`0.044` L

B

` 0.022` L

C

` 0.22` L

D

` 0.44` L

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the total volume occupied by the gas \( N_2O_3 \) at STP after adding 15 mg to \( 4.82 \times 10^{20} \) molecules of \( N_2O_3 \). ### Step-by-Step Solution: **Step 1: Calculate the molar mass of \( N_2O_3 \)** The molar mass of \( N_2O_3 \) can be calculated as follows: - Nitrogen (N) has an atomic mass of approximately 14 g/mol. - Oxygen (O) has an atomic mass of approximately 16 g/mol. ...
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