An aqueous solution is prepared by dissolving 90 g of acetic acid in water to make a 1000 mL solution. Density of solution and mole fraction of solute in the solution.

Explanation

To solve the problem of finding the density of the solution and the mole fraction of solute in the solution, we can follow these steps:

### Step 1: Calculate the number of moles of acetic acid (solute).
To find the number of moles, we use the formula:
\[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]
The molar mass of acetic acid (CH₃COOH) is approximately 60.05 g/mol.
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