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f(1)(x)=x+a,f(2)(x)=x^(2)+bx+c and Delta...

`f_(1)(x)=x+a,f_(2)(x)=x^(2)+bx+c` and `Delta=|[1,1,1],[f_(1)(x_(1)),f_(1)(x_(2)),f_(1)(x_(3))],[f_(2)(x_(1)),f_(2)(x_(2)),f_(2)(x_(3))]|`, then `Delta` is independent of

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