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The angle between vecA = hati + hatj and...

The angle between `vecA = hati + hatj and vecB = hati - hatj` is

A

`45^(@)`

B

`90^(@)`

C

`-45^(@)`

D

`180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b): We know that
`vecAvecB=AB cos theta`
`therefore cos theta (vecAvecB)/(AB)=(hati+hatj).((hati-hatj))/(sqrt(1^(2)+1^(2))sqrt(1^(2)+1^(2))`
`=(1-1)/(sqrt2sqrt2)=0`
or `theta =90^(@)`
The correct option is (b).
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Knowledge Check

  • What is the angle between vecA = 5hati - 5hatj and vecB = 5hati-5hatj ?

    A
    `90^@`
    B
    `45^@`
    C
    `0^@`
    D
    `60^@`

  • If angle between veca = hati - 2hatj + 3hatk and vecb = 2hati + hatj +hatk is theta then the value of sin theta is

    A
    `(3)/(2sqrt7)`
    B
    `(-2)/(sqrt7)`
    C
    `(4)/(3sqrt7)`
    D
    `(5)/(2sqrt7)`

  • vecA and vecB and vectors expressed as vecA = 2hati + hatj and vecB = hati - hatj Unit vector perpendicular to vecA and vecB is:

    A
    `(hati - hatj + hatk)/(sqrt(3)) `
    B
    `(hati + hatj - hatk)/(sqrt(3)) `
    C
    `(hati + hatj + hatk)/(sqrt(3)) `
    D
    `hatk`