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Calculate the total number of electrons ...

Calculate the total number of electrons present in 1.6 g of methane

Text Solution

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16 g of methane contains `=6.022 xx 10^(23)` molecules
1.6 g of methane contains `=(6.022 xx 10^(23) xx 1.6)/16`
One molecule of `CH_(4)` contains = 6+4 =10 electrons
No. of electrons in 1.6 g of methane `=6.022 xx 10^(22) xx 10 = 6.022 xx 10^(23)`
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Knowledge Check

  • The total number of electrons present in 16 g of methane gas is:

    A
    `96.352 xx 10^(23)`
    B
    `48.176 xx 10^(23)`
    C
    `60.22 xx 10^(23)`
    D
    `30.110 xx 10^(23)`

  • What is the total number of electrons present in 0.16 g of methane ?

    A
    `6.023xx10^(22)`
    B
    16
    C
    `12.04xx10^(23)`
    D
    `6.023xx10^(24)`