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A mole is a collection of 6.022 xx 10^23...

A mole is a collection of `6.022 xx 10^23` particles and the number `6.022 xx 10^23` is called Avogadro number. The mass of this number of atoms in an element is equal to its gram atomic mass and mass of this number of molecules in a compound is equal to its gram molecular mass. The volume occupied by this number of molecules of a gas at N.T.P is 22.4 L. When `6.022 xx 10^23` molecules of a substance are dissolved in 1L of solution, the solution is known as 1 molar volume.
The mass of 10 molecules of naphthalene `(C_(10)H_(8))`

A

`2.12 xx 10^(22)`g

B

`2.12 xx 10^(21)`g

C

`2.12 xx 10^(23)` g

D

1280 g

Text Solution

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The correct Answer is:
To find the mass of 10 molecules of naphthalene (C₁₀H₈), we can follow these steps: ### Step 1: Calculate the molar mass of naphthalene (C₁₀H₈) - The molecular formula of naphthalene is C₁₀H₈. - The molar mass can be calculated as follows: - Carbon (C) has an atomic mass of approximately 12 g/mol. - Hydrogen (H) has an atomic mass of approximately 1 g/mol. \[ \text{Molar mass of C}_{10}\text{H}_{8} = (10 \times 12) + (8 \times 1) = 120 + 8 = 128 \text{ g/mol} \] ### Step 2: Relate the molar mass to the number of molecules - We know that 1 mole of naphthalene contains \(6.022 \times 10^{23}\) molecules and has a mass of 128 grams. ### Step 3: Calculate the mass of one molecule of naphthalene - The mass of one molecule can be calculated by dividing the molar mass by Avogadro's number: \[ \text{Mass of one molecule} = \frac{128 \text{ g}}{6.022 \times 10^{23}} \approx 2.12 \times 10^{-22} \text{ g} \] ### Step 4: Calculate the mass of 10 molecules of naphthalene - To find the mass of 10 molecules, multiply the mass of one molecule by 10: \[ \text{Mass of 10 molecules} = 10 \times \left(\frac{128 \text{ g}}{6.022 \times 10^{23}}\right) = \frac{1280 \text{ g}}{6.022 \times 10^{23}} \approx 2.12 \times 10^{-21} \text{ g} \] ### Conclusion - The mass of 10 molecules of naphthalene is approximately \(2.12 \times 10^{-21}\) grams.

To find the mass of 10 molecules of naphthalene (C₁₀H₈), we can follow these steps: ### Step 1: Calculate the molar mass of naphthalene (C₁₀H₈) - The molecular formula of naphthalene is C₁₀H₈. - The molar mass can be calculated as follows: - Carbon (C) has an atomic mass of approximately 12 g/mol. - Hydrogen (H) has an atomic mass of approximately 1 g/mol. ...
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Knowledge Check

  • A mole is a collection of 6.022 xx 10^23 particles and the number 6.022 xx 10^23 is called Avogadro number. The mass of this number of atoms in an element is equal to its gram atomic mass and mass of this number of molecules in a compound is equal to its gram molecular mass. The volume occupied by this number of molecules of a gas at N.T.P is 22.4 L. When 6.022 xx 10^23 molecules of a substance are dissolved in 1L of solution, the solution is known as 1 molar volume. Suppose the chemists would have choosen 10^20 as the number of particles in a mole, the mass of 1 mole of oxygen gas would be:

    A
    `5.32 xx 10^(3)` g
    B
    `5.32 xx 10^(-3)` g
    C
    `5.32 xx 10^(-23)` g
    D
    `5.32 xx 10^(3)` g
  • A mole is a collection of 6.022 xx 10^23 particles and the number 6.022 xx 10^23 is called Avogadro number. The mass of this number of atoms in an element is equal to its gram atomic mass and mass of this number of molecules in a compound is equal to its gram molecular mass. The volume occupied by this number of molecules of a gas at N.T.P is 22.4 L. When 6.022 xx 10^23 molecules of a substance are dissolved in 1L of solution, the solution is known as 1 molar volume. One million atoms of silver (at. mass = 107.81) atoms weigh

    A
    `1.79 xx 10^(-16)` g
    B
    `3.58 xx 10^(-16)` g
    C
    `3.58 xx 10^(6)` g
    D
    `5.32 xx 10^(3)` g
  • 6.022 xx 10^(22) molecules of N_(2) at NTP will occupy a volume of

    A
    22.4 litres
    B
    2.24 litres
    C
    6.02 litres
    D
    6.02 mL
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    Atoms and molecules are so small in size that it is neither possible to count them individually nor possible to determine their mass. These are counted collectively in terms of Avogadro's number. The mass of Avogadro's number of atoms and molecules is known as gram atomic mass and gram molecular mass respectively. The volume occupied by Avogadro's number of molecules of a gas or vapours is known as molar volume. If 3.01 xx 10^(20) molecules are removed from 98 mg of H_(2)SO_(4) , then the number of moles of H_(2)SO_(4) left will be