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The maximum number of electrons can have...

The maximum number of electrons can have principal quantum number `n = 3` and spin quantum number `m_(s) = 1//2` is

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The correct Answer is:
9
No. of orbitals in a shell in n = 3 will be `= n^2` i.e. `3^2 = 9`. Each orbital can have maximum of two electrons, one with `m_s = + 1/2` and the second with `m_s = -1/2`. Hence number of electrons with `m_s = + 1/2` will be 9.
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Knowledge Check

  • The maximum number of electrons that can have principal quantum number n = 3 & spin quantum number m_(s)=-(1)/(2) is :-

    A
    9
    B
    18
    C
    32
    D
    6

  • The maximum number of electrons in the shell with principal quantum number n is equal to

    A
    2n
    B
    `2n^2`
    C
    `2^3`
    D
    `2n^4`

  • The maximum number of electrons in an atom with quantum number n=3, l=2 is

    A
    2
    B
    6
    C
    10
    D
    30