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The reaction between gaseous hydrogen an...

The reaction between gaseous hydrogen and chlorine is
`H_(2)(g) + CI_(2)(g) to 2HCI(g)`
`Delta_(r)H^(@) = -184.0 kJ`
(i) What is the enthalpy of formation of HCI?
How much heat will be liberated at 298 K and 1 atm for the formation of 365 g of HCI?

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If H_2(g) +I_2(g) rarr 2HI(g), Delta H=12.40 kcal . The enthalpy of formation of HI is

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Knowledge Check

  • If H_2(g) +I_2(g) rarr 2HI(g), Delta H=12.40 kcal . The enthalpy of formation of HI is

    A
    `12.4` kcal
    B
    `-12 .4 " kcal "`
    C
    `-6.20 " kcal "`
    D
    6.20 kcal
  • H_(2) (g) +I_(2) (g) rarr 2HI (g), DeltaH=51.9 kJ . According to this, heat of formation of HI is

    A
    `51.9 kJ`
    B
    `-51.9 kJ`
    C
    `-25.95 kJ`
    D
    `25.95 kJ`
  • Reaction H_(2)(g) + I_(2) (g) to 2HI, Delta H_("rxn") = 12.40 Kcal heat of formation of HI will be

    A
    12.40 Kcal
    B
    `- 12.4` Kcal
    C
    ` - 6.20` Kcal
    D
    `6.20` Kcal