The number of compounds showing enantiomers among the following compounds is
Butan-2-ol, 2-Hydroxypropanoic acid, 2-Methylhexane, 2-Chlorobutane, 2-Bromo-2-chlorobutane,
2-Methylbutanoic acid, isopropyl chloride

Explanation

To determine the number of compounds showing enantiomers among the given compounds, we need to identify which of these compounds are optically active. A compound is optically active if it has at least one chiral center, which is a carbon atom bonded to four different groups.

Let's analyze each compound step by step:

1. **Butan-2-ol**:
- Structure: CH3-CH(OH)-CH2-CH3
- The carbon atom with the hydroxyl group (OH) is bonded to four different groups: CH3, CH2CH3, OH, and H.
- Conclusion: Butan-2-ol has a chiral center and is optically active. It can show enantiomers.

2. **2-Hydroxypropanoic acid**:
- Structure: CH3-CH(OH)-COOH
- The carbon atom with the hydroxyl group is bonded to four different groups: CH3, COOH, OH, and H.
- Conclusion: 2-Hydroxypropanoic acid has a chiral center and is optically active. It can show enantiomers.

3. **2-Methylhexane**:
- Structure: CH3-CH(CH3)-CH2-CH2-CH2-CH3
- The carbon atom at position 2 is bonded to two identical groups (CH3), which means it does not have a chiral center.
- Conclusion: 2-Methylhexane is not optically active and cannot show enantiomers.

4. **2-Chlorobutane**:
- Structure: CH3-CH(Cl)-CH2-CH3
- The carbon atom with the chlorine atom is bonded to four different groups: CH3, CH2CH3, Cl, and H.
- Conclusion: 2-Chlorobutane has a chiral center and is optically active. It can show enantiomers.

5. **2-Bromo-2-chlorobutane**:
- Structure: CH3-CH(Br)(Cl)-CH2-CH3
- The carbon atom at position 2 is bonded to four different groups: CH3, CH2CH3, Br, and Cl.
- Conclusion: 2-Bromo-2-chlorobutane has a chiral center and is optically active. It can show enantiomers.

6. **2-Methylbutanoic acid**:
- Structure: CH3-CH(CH3)-CH2-COOH
- The carbon atom at position 2 is bonded to two identical groups (CH3), which means it does not have a chiral center.
- Conclusion: 2-Methylbutanoic acid is not optically active and cannot show enantiomers.

7. **Isopropyl chloride**:
- Structure: CH3-CH(Cl)-CH3
- The carbon atom with the chlorine atom is bonded to two identical groups (CH3), which means it does not have a chiral center.
- Conclusion: Isopropyl chloride is not optically active and cannot show enantiomers.

### Summary of Findings:
- Compounds that can show enantiomers:
- Butan-2-ol
- 2-Hydroxypropanoic acid
- 2-Chlorobutane
- 2-Bromo-2-chlorobutane
- Compounds that cannot show enantiomers:
- 2-Methylhexane
- 2-Methylbutanoic acid
- Isopropyl chloride

### Final Count:
The number of compounds showing enantiomers is **4**.