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0.2 m aqueous solution of a weak acid (H...

0.2 m aqueous solution of a weak acid (HX) is 20% dissociated. The boiling point of this solution is ( `K_(b)` for water `= 0.52 Km^(-1)`)

A

`101.04^(@)C`

B

`100.104^(@)C`

C

`100.1248^(@)C`

D

`100.52^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
`{:(" HX(aq)",rarr," H"^(+),+," X"^(-)),(m(1-0.20),,m(0.20),,m(0.20)):}`
Molal conc. of soln.
`=m(1-0.20)+0.20m +0.20m`
`=1.20m`
`DeltaT_(b)=K_(b) xx m`
`=0.52 xx 1.20(0.2)=0.1248`
Boiling point `=100.1248^(@)C`
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Knowledge Check

  • A 0.1 M solution of a weak acid HA is 1% dissociated. The approximate value of dissociation constant is :

    A
    `1.0xx10^(-4)mol L^(-1)`
    B
    `0.1xx10^(-2)mol L^(-1)`
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    D
    `0.1xx10^(-4)mol L^(-1)`

  • The pH of a 0.1 M aqueous solution of a weak acid (HA) is 4. what is its degree of dissociation?

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    `1%`
    B
    `10%`
    C
    `50%`
    D
    `25%`

  • 0.85% aqueous solution of NaNO_(3) is apparently 90% dissociated . The osmotic pressure of solution at 300 K is

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