What is the area of the shaded region? (FIGURE) `32-4\ pi\ s qdotu n i t s` (b) `32-8\ pi\ s qdotu n i t s` (c) `16-4\ pi\ s qdotu n i t s` (d) `16-8\ pi\ s qdotu n i t s`

The area of a circle whose radius is the diagonal of a square whose area is 4 sq. units is 16pi s qdotu n i t s (b) 4pi s qdotu n i t s (c) 6pi s qdotu n i t s (d) 8pi s qdotu n i t s

The graph of y^2+2x y+40|x|=400 divides the plane into regions. Then the area of the bounded region is (a)200s qdotu n i t s (b) 400s qdotu n i t s (c)800s qdotu n i t s (d) 500s qdotu n i t s

The area of the region bounded by x=0,y=0,x=2,y=2,ylt=e^x a n dygeq1nx is 6-41n2s qdotu n i t s (b) 41n2-2s qdotu n i t s 21n2-4s qdotu n i t s (d) 6-21n2s qdotu n i t s

A tangent having slope of -4/3 to the ellipse (x^2)/(18)+(y^2)/(32)=1 intersects the major and minor axes at point Aa n dB , respectively. If C is the center of the ellipse, then the area of triangle A B C is 12s qdotu n i t s (b) 24s qdotu n i t s 36s qdotu n i t s (d) 48s qdotu n i t s

Let f(x)=x^3+3x+2a n dg(x) be the inverse of it. Then the area bounded by g(x) , the x-axis, and the ordinate at x=-2a n dx=6 is 1/4s qdotu n i t s (b) 4/3s qdotu n i t s 5/4s qdotu n i t s (d) 7/3s qdotu n i t s

The area of the region enclosed between the curves x=y^2-1a n dx=|y|sqrt(1-y^2) is 1s qdotu n i t s (b) 4/3s qdotu n i t s 2/3s qdotu n i t s (d) 2s qdotu n i t s

The area bounded by the curve f(x)=x+sinx and its inverse function between the ordinates x=0a n dx=2pi is 4pis qdotu n i t s (b) 8pis qdotu n i t s 4s qdotu n i t s (d) 8s qdotu n i t s

The area bounded by the two branches of curve (y-x)^2=x^3 and the straight line x=1 is 1/5s qdotu n i t s (b) 3/5s qdotu n i t s 4/5s qdotu n i t s (d) 8/4s qdotu n i t s

The area bounded by the curve a^2y=x^2(x+a) and the x-axis is (a^2)/3s qdotu n i t s (b) (a^2)/4s qdotu n i t s (3a^2)/4s qdotu n i t s (d) (a^2)/(12)s qdotu n i t s

A straight line passing through P(3,1) meets the coordinate axes at Aa n dB . It is given that the distance of this straight line from the origin O is maximum. The area of triangle O A B is equal to (50)/3s qdotu n i t s (b) (25)/3s qdotu n i t s (20)/3s qdotu n i t s (d) (100)/3s qdotu n i t s