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Arrange the following ions in the increa...

Arrange the following ions in the increasing order of unpaired electrons `Na^+,Cu^(+1),N^(-3),O^-,P` and Cr

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To solve the problem of arranging the ions `Na^+, Cu^(+1), N^(-3), O^-, P,` and `Cr` in increasing order of unpaired electrons, we will analyze each ion one by one, determine the number of unpaired electrons for each, and then arrange them accordingly. ### Step-by-Step Solution: 1. **Determine the number of electrons in each ion:** - **Na⁺**: Sodium (Na) has an atomic number of 11. When it loses one electron to form Na⁺, it has 10 electrons. The electron configuration is the same as Neon (Ne), which is 1s² 2s² 2p⁶. There are **0 unpaired electrons**. - **Cu⁺**: Copper (Cu) has an atomic number of 29. The electron configuration is [Ar] 4s¹ 3d¹⁰. When it loses one electron to form Cu⁺, it becomes [Ar] 3d¹⁰. There are **0 unpaired electrons**. ...
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