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Find the three terms in AP, whose sum is...

Find the three terms in AP, whose sum is 36 and product is 960.

Text Solution

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Let the three terms of an AP be `(a-d), a and (a+d)`.
Sum of these terms is `3a`.
`3a = 36 rArr a = 12`
Product of these three terms is
`(a+d)a (a -d) = 960`
`rArr (12+d) (12-d)= 80`
`rArr 144 - d^(2) = 80 rArr d = pm 8`
Taking `d=8`, we get the terms as `4, 12 and 20`.
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