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The ratio of 1st and 2nd classes train f...

The ratio of 1st and 2nd classes train fairs between two stations is 3 : 1 and that of the number of pas- sengers travelling between these stations by 1st and 2nd classes is 1 : 50. If on a particular day, X 2650 be collected from the passengers travelling between these stations, then find the amount collected from 2nd class passengers.

A

X 3000

B

X 3500

C

X 2800

D

X 2500

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The correct Answer is:
To solve the problem step by step, we will use the given ratios of train fares and the number of passengers to find the amount collected from 2nd class passengers. ### Step 1: Understand the Ratios We are given: - The ratio of 1st class fare to 2nd class fare is 3:1. - The ratio of the number of passengers traveling in 1st class to those in 2nd class is 1:50. ### Step 2: Determine the Total Ratio of Fares Let’s denote: - The fare for 1st class as \( F_1 = 3x \) - The fare for 2nd class as \( F_2 = x \) Now, we can express the total fare collected from both classes based on the number of passengers: - Let the number of 1st class passengers be \( P_1 = y \) - Let the number of 2nd class passengers be \( P_2 = 50y \) ### Step 3: Calculate Total Amount Collected The total amount collected from both classes can be expressed as: \[ \text{Total Amount} = (F_1 \cdot P_1) + (F_2 \cdot P_2) \] Substituting the values: \[ \text{Total Amount} = (3x \cdot y) + (x \cdot 50y) = 3xy + 50xy = 53xy \] ### Step 4: Set Up the Equation We know that the total amount collected is Rs. 2650. Therefore, we can set up the equation: \[ 53xy = 2650 \] ### Step 5: Solve for \( xy \) To find \( xy \): \[ xy = \frac{2650}{53} \] Calculating this gives: \[ xy = 50 \] ### Step 6: Calculate the Amount Collected from 2nd Class Passengers Now, we need to find the amount collected from 2nd class passengers: \[ \text{Amount from 2nd class} = F_2 \cdot P_2 = x \cdot 50y \] Since we have \( xy = 50 \), we can substitute: \[ \text{Amount from 2nd class} = x \cdot 50y = 50 \cdot x \] From \( xy = 50 \), we can express \( x \) as: \[ x = \frac{50}{y} \] Substituting back, we find: \[ \text{Amount from 2nd class} = 50 \cdot \frac{50}{y} = 2500 \] ### Final Answer The amount collected from 2nd class passengers is Rs. 2500. ---
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