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An urn contains 6 red and 9 blue t...

An urn contains 6 red and 9 blue two balls are drawn from urn one after another without replacement .
Find the probability of drawing a red ball when a blue ball has been drawn from the urn .

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The correct Answer is:
To solve the problem, we need to find the probability of drawing a red ball (event A) given that a blue ball (event B) has already been drawn from the urn. ### Step-by-Step Solution: 1. **Identify the Total Number of Balls**: - Initially, there are 6 red balls and 9 blue balls in the urn. - Total number of balls = 6 (red) + 9 (blue) = 15 balls. **Hint**: Always start by determining the total number of items in the set. 2. **Understand the Scenario After Drawing a Blue Ball**: - Since we are drawing without replacement, after drawing one blue ball, the number of balls left in the urn will be: - Total balls left = 15 - 1 = 14 balls. - The number of red balls remains the same, which is 6 red balls. **Hint**: Remember that drawing without replacement changes the total count of items but not the count of the remaining items of the same type. 3. **Calculate the Probability of Drawing a Red Ball After Drawing a Blue Ball**: - We need to find the probability of event A (drawing a red ball) given event B (a blue ball has been drawn). - The probability can be expressed as: \[ P(A|B) = \frac{\text{Number of favorable outcomes for A}}{\text{Total outcomes after B}} \] - Here, the number of favorable outcomes for A (drawing a red ball) = 6 (since all red balls are still in the urn). - The total outcomes after drawing a blue ball = 14 (total balls left). **Hint**: Use the conditional probability formula \( P(A|B) = \frac{P(A \cap B)}{P(B)} \) when applicable, but in this case, you can directly calculate since we know the outcomes. 4. **Substituting the Values**: - Now substituting the values into the formula: \[ P(A|B) = \frac{6}{14} \] 5. **Simplifying the Fraction**: - Simplifying \( \frac{6}{14} \): \[ P(A|B) = \frac{3}{7} \] **Hint**: Always simplify your fractions to their lowest terms for clarity. ### Final Answer: The probability of drawing a red ball after a blue ball has been drawn is \( \frac{3}{7} \).
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Knowledge Check

  • An urn contains 4 black and 6 red balls. If two balls are drawn at random from the urn without replacement ,then the probability that both are black is

    A
    `1/5`
    B
    `1/(15)`
    C
    `2/(15)`
    D
    `(13)/(15)`
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