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A pendulum is formed by pivoting a long ...

A pendulum is formed by pivoting a long thin rod of length L and mass m about a point P on the rod which is a distance d above the centre of the rod as shown.

The time period of this pendulum when d = L/2 will be

A

`2pi sqrt((2l)/(3g))`

B

`2pi sqrt((3l)/(2g))`

C

`4pi sqrt((l)/(3g))`

D

`(2pi)/(3) sqrt((2l)/(g))`

Text Solution

Verified by Experts

The correct Answer is:
A
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Knowledge Check

  • A pendulum is formed by pivoting a long thin rod of length L and mass m about a point P on the rod which is a distance d above the centre of the rod as shown. Time period will be minimum when d is equal to

    A
    `(L)/(sqrt12)`
    B
    `(L)/(sqrt6)`
    C
    `L//4`
    D
    `L//2`

  • A pendulum is formed by pivotting a long thin rod of length L and mass m about a point P on the rod which is a distance d above the centre of the rod as shown. As d changes from L/2 to zero

    A
    Time period increases continuously
    B
    Time period decreases continuously
    C
    Time period first increases then decrease
    D
    Time period first decreases then increase

  • A pendulum is formed by pivoting a long thin rod of length L and mass m about a point P on the rod which is a distance d above the centre of the rod as shown. As d changes from L/2 to zero. Time period

    A
    increases continuously
    B
    decreases continuously
    C
    first increases then decrease
    D
    first decreases then increase
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