Home
Class 12
PHYSICS
A pendulum is formed by pivoting a long ...

A pendulum is formed by pivoting a long thin rod of length L and mass m about a point P on the rod which is a distance d above the centre of the rod as shown.

The time period of this pendulum when d = L/2 will be

A

`2pi sqrt((2l)/(3g))`

B

`2pi sqrt((3l)/(2g))`

C

`4pi sqrt((l)/(3g))`

D

`(2pi)/(3) sqrt((2l)/(g))`

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    FIITJEE|Exercise Assertion Reason type|1 Videos
  • SIMPLE HARMONIC MOTION

    FIITJEE|Exercise Numerical Based Questions|6 Videos
  • SIMPLE HARMONIC MOTION

    FIITJEE|Exercise Solved Problems (Objective)|16 Videos
  • SEMICONDUCTOR AND DEVICE

    FIITJEE|Exercise SOLVED PROBLEMS Objective: Level-I|20 Videos
  • TEST PAPERS

    FIITJEE|Exercise PHYSICS|747 Videos

Similar Questions

Explore conceptually related problems

A pendulum is formed by pivoting a long thin rod about a point on the rod. In a series of experiments, the period is measured as a function of the distance x between the pivot point and the rod's center. (a) If the rod's length is L= 2.20 m and its mass is m= 22.1g, what is the minimum period? (b) If x is chosen to minimize the period and then L is increased does the period increase, decrease, or remain the same? (c ) If, instead, m is increased without L increasing does the period increase, decrease or remain the same?

Two uniform thin rods each of length L and mass m are joined as shown in the figure. Find the distance of centre of mass the system from point O

Knowledge Check

  • A pendulum is formed by pivoting a long thin rod of length L and mass m about a point P on the rod which is a distance d above the centre of the rod as shown. Time period will be minimum when d is equal to

    A
    `(L)/(sqrt12)`
    B
    `(L)/(sqrt6)`
    C
    `L//4`
    D
    `L//2`
  • A pendulum is formed by pivotting a long thin rod of length L and mass m about a point P on the rod which is a distance d above the centre of the rod as shown. As d changes from L/2 to zero

    A
    Time period increases continuously
    B
    Time period decreases continuously
    C
    Time period first increases then decrease
    D
    Time period first decreases then increase
  • A pendulum is formed by pivoting a long thin rod of length L and mass m about a point P on the rod which is a distance d above the centre of the rod as shown. As d changes from L/2 to zero. Time period

    A
    increases continuously
    B
    decreases continuously
    C
    first increases then decrease
    D
    first decreases then increase
  • Similar Questions

    Explore conceptually related problems

    A thin uniform rod of length L is bent at its mid point as shown in the figure. The distance of the centre of mass from the point O is

    The moment ofinertia ofa thin rod of length L and mass M about an axis passing through a point at a distance (L)/(3) from one of its ends and perpendicular to the rod, is

    The moment of inertia of a uniform thin rod of length L and mass M about an axis passing through a point at a distance of L/3 from one of its ends and perpendicular to the rod is

    The moment of inertia of a uniform thin rod of length L and mass M about an axis passing through a point at a distance of L//3 from one of its ends and perpendicular to the rod is

    Two identical thin uniform rods of length L each are joined to form T shape as shown in the figure. The distance of centre of mass from D is