The reaction, `(CH_(3))_(3)C-Brto(CH_(3))_(3) C^(+) + Br^(-)` is an example of

Options

A. Homolytic fission
B. Heterolytic fission
C. Cracking
D. All the above

Answer

To determine the type of reaction represented by the equation

\[ (CH_3)_3C-Br \rightarrow (CH_3)_3C^+ + Br^- \]

we need to analyze the process occurring during the reaction.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactant is tert-butyl bromide, \((CH_3)_3C-Br\).
- The products are a tert-butyl cation, \((CH_3)_3C^+\), and a bromide ion, \(Br^-\).

2. **Understand the Bond Breaking**:
- In the reaction, the bond between the carbon atom and the bromine atom is broken.
- The bond breaking involves the transfer of electrons.

3. **Determine the Nature of Bond Breaking**:
- **Homolytic Fission**: This occurs when the bond breaks evenly, and each atom takes one of the shared electrons, resulting in the formation of radicals. This is not the case here, as we do not see radicals being formed.
- **Heterolytic Fission**: This occurs when the bond breaks unevenly, with one atom taking both of the bonding electrons. In this case, bromine, being more electronegative, takes both electrons, resulting in the formation of a bromide ion \(Br^-\) and a positively charged tert-butyl cation \((CH_3)_3C^+\).

4. **Conclusion**:
- Since the bond between carbon and bromine breaks in such a way that bromine takes both electrons, this reaction is an example of **Heterolytic fission**.

### Final Answer:
The reaction \((CH_3)_3C-Br \rightarrow (CH_3)_3C^+ + Br^-\) is an example of **Heterolytic fission**.

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