1. Find the areas of the following figures by counting square:

Explanation

(a)We know that area of 1 square = 1 sq. unit
Now, the total number of squares in the figure = 9
Area of 9 squares `= 9 xx 1 `sq. unit
= 9 sq. units.
Therefore, the area of the given figure is 9 sq. units.
(b)There are 5 squares in the given figure.
So, Area of 5 squares `= 5 xx 1` sq. unit
= 5 sq. units
Therefore, the area of the figure is 5 sq. units
(c)There are 2 complete squares and 4 half squares in the figure.
So, Area of the figure =` 2 xx 1 + 4 xx 1/2 = 2 + 2` sq. units= 4 sq. units
Thus, the area of the given figure is 4 sq. units.
`(d)`There are 8 squares in the figure.
So, the area of the figure `= 8 xx 1` sq. unit
= 8 sq. units.
Therefore, the area of the given figure is 8 sq. units
(e)There are 10 squares in the figure.
So, the area of the figure` = 10 xx 1` sq. unit `= 10` sq units.
Thus, the area of the figure is 10 sq. units
(f)There are` 2 `complete squares and` 4 `half squares in the figure.
So, Area of the figure` = (2 xx 1 + 4 xx 1/2)`
`= (2 + 2)` sq units= 4 sq. units.
Thus, area of the given figure is` 4 `sq. units
(g)There are `4 `complete squares and` 4` half squares in the figure.
So, Area of the given figure` = (4 xx 1 + 4 xx 1/2)`
`= (4 + 2)` sq. units
`= 6` sq. units.
Therefore, the area of the given figure is 6 sq. units
(h)There are` 5 `squares in the figure.
So, Area of the figure` = 5 xx 1` sq. unit
`= 5 `sq. units.
Thus, the area of the given figure is 5 sq. units.
(i)There are` 9 `squares in the figure.
So, Area of the figure` = 9 xx 1= 9 `sq. units
Thus, the area of the given figure is 9 sq. units
(j)There are 2 complete squares and 4 half squares in the figure.
So, Area of the figure` =(2 xx1 + 4 xx 1/2)` sq. units= (2 + 2) sq. units
= 4 sq. units.
Thus, the area of the figure is 4 sq. units.
(k)There are` 4` complete squares and` 2` half squares in the figure.
So, Area of the figure` = (4 xx 1 + 2 × 1/2)` sq. units
`= (4 + 1) `sq. units
`= 5 `sq. units
Thus, the area of the figure is `5` sq. units
(l)There are` 4` complete squares, `3` greater than half squares and` 2` halfnsquares in the figure.
So, Area of the figure` = (4 xx 1 + 3 xx 1 + 2 × 1/2) `sq units
`= (4 + 3 + 1)` sq units
= 8 sq units
(m)There are` 6` complete squares and` 8 `greater than half squares in the figure.
So, Area of the figure` = (6 xx 1 + 8 xx 1)` sq units
`= 6 + 8` sq. units
`= 14` sq. units
(n)There are` 9 `complete squares and` 9` greater than half squares in the figure.
So, Area of the figure` = (9 xx 1 + 9 xx 1)` sq units
`=(9 + 9)` sq units
`= 18 `sq units.