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The increasing order (lowest first) for ...

The increasing order (lowest first) for the values of `e//m` (charge//mass) for electron `(e)`, proton `(p)`, neutron `(n)`, and alpha particle `(alpha)` is

A

`e,p,n,alpha`

B

`n,p,e,alpha`

C

`n,p,alpha,e`

D

`n,alpha,p,e`

Text Solution

Verified by Experts

The correct Answer is:
D
`e/m` for (i) neutron =`0/1`=0
(ii)`alpha`-particle=`2/4=0.5`
(iii)proton=`1/1` =1
(iv)electron=`1/(1//1837)=1837`
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