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the diameter of a wire was measured as 1.65 mm with a certain faulty screw gauge when the correct diameter was 1.60 mm. what type of error does the faulty screw gauge have?

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Knowledge Check

  • The diameter of a wire is measured by using a screw gauge having least count 0.01mm . If the diameter is found to be 0.20mm , then the error in the cross-section of the wire will be

    A
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    B
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    C
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    A
    `(Delta W)/(W)+(Delta L)/(L)+(Delta d)/(d)+(Delta l)/(l)`
    B
    `(Delta W)/(W)+(Delta L)/(L)-(2Delta d)/(d)+(Delta)/(l)`
    C
    `(Delta W)/(W)+(Delta L)/(L)+(2Delta d)/(d)+(Delta l)/(l)`
    D
    `(Delta W)/(W)-(Delta L)/(L)+(Delta d)/(d)+(Delta l)/(l)`
  • Using Searle's apparatus while determining the Young's modulus of a wire, a girl is taking measurements of different parameters : Length of the wire, L, is 30 cm, which is measured with a millimeter scale , diameter of the wire, d, is 1 mm, which is measured with a screw gauge. (Least count of the screw gause is 0.01 mm, least count of the spherometer attached to the apparatus frame is 0.005 mm, spherometer attached to the apparatus frame is 0.005 mm , spherometer measured the extension e of the wire , W is the weight of the loads.) The parameter that should be measured more carefully is

    A
    load on the hanger
    B
    length of the wire
    C
    diameter of the wire
    D
    extension of the wire
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