Home
Class 9
PHYSICS
An alpha particle and a proton fall thro...

An `alpha` particle and a proton fall through the same potential difference. Find the ratio of their momentra if the mass of the `alpha` particle is four times that of the proton.

Text Solution

Verified by Experts

(i) Compare the velocity of an `alpha` particle with that of a proton in the same potential difference. To compare the velocities equate the kinetic energy. We know that momentum p = mv.
Compare mass and velocity of `alpha` particle with that of proton to find the relation between their momebta.
(ii) `sqrt(8) : 1`
Promotional Banner

Topper's Solved these Questions

  • MODERN PHYSICS

    PEARSON IIT JEE FOUNDATION|Exercise Level 2|14 Videos

  • MEASUREMENTS

    PEARSON IIT JEE FOUNDATION|Exercise Level 3|8 Videos

  • SIMPLE MACHINES

    PEARSON IIT JEE FOUNDATION|Exercise Level- 3|10 Videos

Similar Questions

Explore conceptually related problems

A proton and an alpha -particle are accelerated through same potential difference. Find the ratio of their de-Brogile wavelength.

An alpha - particle and a proton are accelerated through same potential difference. Find the ratio (v_(a)//v_(p)) of velocities acquired by two particles.

An alpha -particle and a proton are accelerated from rest through the same potential difference V. Find the ratio of de-Broglie wavelength associated with them.

A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha -particle is

A proton and an alpha particle are accelerated through the same potential difference. The ratio of the wavelengths associated with the proton to that associated with the alpha particle is

The ratio of the e/m values of a proton and an alpha -particle is:

A proton and an alpha particle accelerated through the same potential difference enter a region of uniform magnetic field normally if the radius of the proton orbit is 10 cm ten radius of alpha particle is