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The specific gravity (or relative densit...

The specific gravity (or relative density) of gold is 19. Find the mass of a gold body that displaces `25cm^(3)` of water when immersed in it.

Text Solution

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Given, specific gravity of gold = 19
`rArr` relative density of gold = 19
`:.` Density of gold = `19" g cm^(-3)`.
When the gold body is immersed in water, it displaces `25cm^(3)`
`rArr` volume of the gold body = `25cm^(3)`
`:.` Mass of the gold body = (volume) (density)
`=(25"cm"^(3))" "(19"g cm"^(-3))`
= 475 grams
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