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The amount of H(2)O(2) present in 1 L of...

The amount of `H_(2)O_(2)` present in 1 L of `1*5 NH_(2)O_(2)` solution is

A

25.5 g

B

3.0 g

C

8.0 g

D

2.5 g

Text Solution

Verified by Experts

The correct Answer is:
A
Molecular weight of `H_(2)O_(2)=34`
Equivalent weight of `H_(2)O_(2)=17`
`therefore" 1 L of N "H_(2)O_(2)" has "="17 g of "H_(2)O`
`therefore" 1 L of 1.5 N "H_(2)O_(2)" has "=1.5xx17="25.5 g of "H_(2)O_(2)`
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Knowledge Check

  • The amount of H_(2)O_(2) present in 1 L of 1*5 NH_(2)O_(2) sodium is

    A
    `2*5` g
    B
    `25*5` g
    C
    `3*0` g
    D
    `8*0` g.

  • The amount of H_(2)O_(20 present in 1L of 1.5 NH_(2)O_(2) solution is

    A
    `2.5 g`
    B
    `25.5g`
    C
    `3.0g`
    D
    `8.0g`

  • 1.78N of H_(2)O_(2) solution is :

    A
    10 volumes of `H_(2)O_(2)`
    B
    3.03% `((w)/(v))` of `H_(2)O_(2)`
    C
    2.56M `H_(2)O_(2)`
    D
    1 mL `H_(2)O_(2)` liberates 10 mL of `O_(2)` at STP