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How would you account for the following?...

How would you account for the following?
(i) `Cr^(2+)` is reducing in nature while with the same d-orbital configuration `(d^14) Mn^(3+)` is an oxidising agent.
(ii) In a transition series of metals, the metal which exhibits the greatest number of oxidation states occurs in the middle of the series.
(iii) Metal-metal bonding is more frequent for the 4d and the 5d series of transition metals than for the 3d series.

Answer

Step by step text solution for How would you account for the following? (i) Cr^(2+) is reducing in nature while with the same d-orbital configuration (d^14) Mn^(3+) is an oxidising agent. (ii) In a transition series of metals, the metal which exhibits the greatest number of oxidation states occurs in the middle of the series. (iii) Metal-metal bonding is more frequent for the 4d and the 5d series of transition metals than for the 3d series. by CHEMISTRY experts to help you in doubts & scoring excellent marks in Class 12 exams.

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Explore conceptually related problems

How would you account for the following: (i) Cr^(2+) is reducing in nature while with the same d-orbital configuration (d^(4)) Mn^(3+) is an oxidising agent (ii) In a transition series of metals, the metal which exhibits the greatest number of oxidation state occurs in the middle of the series.

In the transition series of metals, the metal which exhibits the greatest number of oxidation states occurs in the middle of the series. Explain.

Knowledge Check

  • Which of the 3d-seres of the transition metals exhibits the leagest number of oxidation states ?

    A
    Cr
    B
    Mn
    C
    Fe
    D
    Co

  • Metal-Metal bonding is more frequent in 4d or 5d series than in 3d series due to

    A
    Their greater enthalpy of atomisation
    B
    Large size of orbitals which participate in bonding
    C
    their ability to involve both ns and (n-1)d orbitals in bond formation
    D
    The comparable size of 4d and 5d series elements

    • Similar Questions

    Explore conceptually related problems

    How would you account for the following : (i) Cr^(2+) is reducing in nature while with the same d-orbital configuration (d^(4)),Mn^(2+) is oxidising in nature. (ii) In the transition series of metals, the metal which exhibits the greatest number of oxidation states occurs in the middle of the series.

    Metal-Metal bondin is more extensive in the 4d and 5d series of transition elements than the 3d series. Explain.

    Which of the 3d series of the transition metals exhibits the largest number of oxidation states and why ?

    Which of the 3d series of the transition metals exhibits the largest number of oxidation states and why ?

    Which of the 3d series of the transition metals exhibits the largest number of oxidation states and why?

    Explain giving a suitable reason for each of the following : (i) Transition metals and their compounds are generally found to be good catalysts. (ii) Metal-metals bonding is more frequent for the 4d and the 5d series of transitions metals than that for the 3d series.

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