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How do you prepare : (i) k(2)MnO(4) fr...

How do you prepare :
(i) `k_(2)MnO_(4) from MnO_(2)`?
(ii) `Na_(2)Cr_(2)O_(7) from NaCrO_(4)`?
(b) Account for the following :
(i) `Mn^(2+)` is more stable then `Fe^(2+)` towards oxidation to + 3 state.
(ii) The enthelpy of atomization is lowest for Zn in 3d series of the transition elements.
(iii) Actinoid elements show wide range of oxidation states.

Answer

Step by step text solution for How do you prepare : (i) k_(2)MnO_(4) from MnO_(2)? (ii) Na_(2)Cr_(2)O_(7) from NaCrO_(4)? (b) Account for the following : (i) Mn^(2+) is more stable then Fe^(2+) towards oxidation to + 3 state. (ii) The enthelpy of atomization is lowest for Zn in 3d series of the transition elements. (iii) Actinoid elements show wide range of oxidation states. by CHEMISTRY experts to help you in doubts & scoring excellent marks in Class 12 exams.

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Explore conceptually related problems

(a) How will you prepare : (i) K_(2)MnO_(4) from MnO_(2) ? (ii) Na_(2)Cr_(2)O_(7) from Na_(2)CrO_(4) ? (b) Account for the following: (i) Mn^(2+) is more stable than Fe^(2+) towards oxidation to +3 state. (ii) The enthalpy of atomisation is lowest for Zn is 3d series of the transition elements. (iii) Actinoid elements show wide range of oxidation states.

(a) How do you prepare : (i) K_(2)MnO_(4) from MnO_(2) (ii) Na_(2)Cr_(2)O_(7) from Na_(2)CrO_(4) ? (b) Account for the following : (i) Mn^(2+) is more stable than Fe^(2+) towards oxidation to +3 state. (ii) The enthalpy of atomisation is lowest for Zn in 3d series of transition elements. (iii) Actinoid elements show wide range of oxidation states. or (i) Name the elements of 3d transition series which shows maximum number of oxidation states. Why dows it show so ? (ii)Which transition element of 3d series has positive E_(M^(+)//M)^(@) value and why ? (iii) Out of Cr^(3+) and Mn^(3+) which is stronger oxidizing agent and why ? (iv) Name a member of the lanthanoid series which is well known to exhibit +2 oxidation state. (v) Complete the equation : MnO_(4)^(-) +8 H^(+) + 5e^(-) rarr

Knowledge Check

  • In which of the following is there an element with the same oxidation state as that of chromium in K_(2)Cr_(2)O_(7) ?

    A
    `Cl_(2)O_(7)`
    B
    `[Fe(CN)_(6)]^(3-)`
    C
    `VO^(2+)`
    D
    `K_(2)MnO_(4)`

    • Similar Questions

    Explore conceptually related problems

    How would you prepare (i) K_(2)MnO_(4) and MnO_(2) ? (ii) Na_(2)Cr_(2)O_(7) from Na_(2)CrO_(4) ?

    Account for the following : (i) Oxidizing power in the series : VO^(2+) lt Cr_(2)O_(7)^(2-) lt MnO_(4)^(-) (ii) Actinoid contraction is greater from element to element than lanthanoid contraction. (iii) Oxoanion of a metal show higher oxidation states.

    (a) Account for the following : (i) Mn_(2)O_(7) is acidic whereas MnO is basic. (ii) Though copper has completely filled d-orbital (d^(10)) yet it is considered as a transition metal. (iii) Actinoids show wide range of oxidation states. (b) Write the preparation of potassium permanganate from pyrolusite ore (MnO_(2)) .

    State the reason for the following : (i) Cu (I) ion is not stable in an aqueous solution. (ii) Unlike Cr^(3+),Mn^(2+),Fe^(3+) and the subsequent other M^(2+) ions of the 3d series, the 4d and 5d series metals generally do not form stable oxidation states.

    Write the preparation of following : (i) KMnO_4 from K_2MnO_4 (ii) Na_2CrO_4 from FeCr_2O_4 (iii) Cr_2O_(7)^(2-) from Cr_2O_(4)^(2-)

    State reasons for the following: (i) Cu (1) ion is not stable in an aqueous solution. (ii) Unlike Cr^(3+), Mn^(2+), Fe^(3+) and the subsequent other M^(2+) ions of the 3d series of elements, the 4d and 5d series metals generally do not form stable cationic species.

    Assign reasons for each of the following : (i) Manganese exhibits the highest oxidation state of +7 . (ii) Unlike Cr^(3+), Mn^(2+), Fe^93+) and the subseuent M^(3+) ions of 3d series of elements , the 4d an 5d series metals generally do not form stable cationic species.

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