Home
Class 12
MATHS
tan^(-1)(logx)...

`tan^(-1)(logx)`

Text Solution

AI Generated Solution

To differentiate the function \( y = \tan^{-1}(\log x) \), we will use the chain rule and the derivative of the inverse tangent function. ### Step-by-Step Solution: 1. **Identify the function**: \[ y = \tan^{-1}(\log x) \] ...
Promotional Banner

Similar Questions

Explore conceptually related problems

If y=tan^(-1)[(logex)/(log (e/x))] + tan^(-1)[(8-logx)/(1+8 logx)] , then (d^(2)y)/(dx^(2)) is

If y=tan^(-1)[(1-2logx)/(1+2logx)]+tan^(-1)[(3+2logx)/(1-6logx)]," then "((dy)/(dx))_(x=3)+((dy)/(dx))_(x=-3)=

y= tan^(2)(logx^(3)) ,Find dy/dx

x^(x)(1+logx)

If f(x)=cos^(-1)[(1-(logx)^2)/(1+(logx)^2)] , then the value of f'(e) is equal to........

int{(1)/((logx))-(1)/((logx)^(2))}dx=?

int[(1)/(logx)-(1)/((logx)^(2))]dx=

Solve the equation (1-2(2logx)^(2))/(logx-2(logx)^(2))=1

int(1)/(x(logx))dx=?

int(1)/(x(1+logx)^(3))+c