Solve the differential equation
`(1+y^(2))(1+log x) dx +x dy =0,` it being given that y = 1 when x = 1

Explanation

To solve the differential equation

\[ (1+y^2)(1+\log x) \, dx + x \, dy = 0, \]

given that \( y = 1 \) when \( x = 1 \), we can follow these steps:

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