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If the equation x^2+y^2+2h x y+2gx+2fy+c...

If the equation `x^2+y^2+2h x y+2gx+2fy+c=0` represents a circle, then the condition for that circle to pass through three quadrants only but not passing through the origin is `f^2> c` (b) `g^2>2` `c >0` (d) `h=0`

A

`f^(2) lt c`

B

`g^(2) gtc`

C

`cgt0`

D

`h =0`

Text Solution

Verified by Experts

The correct Answer is:
1,2,3,4
The given circle is `x^(2)+y^(2)+2hxy+2gx+2fy+c=0` (i)
For (i) to represent a circle, `h=0`
So, the given circle is
`x^(2)+y^(2)+2gx+2fy+c=0` (ii)

For circle (ii) to pass through the quadrants only.
I. Circle must cut x-axis `i.e., g^(2)-c gt0`
II. Circle must cut y-axis `g^(2)-cgt0`
III. The origin should lie outside circle `(ii) , i.e., cgt0`
Therefore, the required conditions are `g^(2) gt c, f^(2) gt c, cgt 0` and `h=0`.
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