The value of osmotic pressure of a 0.2 M aqueous solution at 293 K is

Options

A. 8.4 atm
B. 0.48 atm
C. 4.8 atm
D. 4.0 atm

Explanation

To calculate the osmotic pressure of a 0.2 M aqueous solution at 293 K, we can use the formula for osmotic pressure (π):

\[ \pi = C \cdot R \cdot T \]

Where:
- \( \pi \) = osmotic pressure
- \( C \) = molarity of the solution (in moles per liter)
- \( R \) = ideal gas constant
- \( T \) = temperature in Kelvin

### Step-by-Step Solution:

**Step 1: Identify the values given in the problem.**
- Molarity (C) = 0.2 M
- Temperature (T) = 293 K
- Ideal gas constant (R) = 0.082 L·atm/(K·mol)

**Step 2: Substitute the values into the osmotic pressure formula.**
\[ \pi = 0.2 \, \text{mol/L} \times 0.082 \, \text{L·atm/(K·mol)} \times 293 \, \text{K} \]

**Step 3: Perform the multiplication.**
- First, calculate \( 0.2 \times 0.082 \):
\[ 0.2 \times 0.082 = 0.0164 \]

- Then multiply by 293:
\[ 0.0164 \times 293 = 4.8 \, \text{atm} \]

**Step 4: State the final result.**
The osmotic pressure of the 0.2 M aqueous solution at 293 K is:
\[ \pi = 4.8 \, \text{atm} \]

### Final Answer:
The value of osmotic pressure of a 0.2 M aqueous solution at 293 K is 4.8 atm.

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