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Difference in .(17)Cl^(35) and .(17)Cl^(...

Difference in `._(17)Cl^(35) and ._(17)Cl^(37)` is of

A

Atomic number

B

Number of protons

C

Number of neutrons

D

Number of electrons

Text Solution

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The correct Answer is:
To find the difference between the isotopes \( _{17}^{35}\text{Cl} \) and \( _{17}^{37}\text{Cl} \), we can follow these steps: ### Step 1: Identify the Atomic Number The atomic number of chlorine (Cl) is 17. This means both isotopes have the same number of protons. ### Step 2: Identify the Mass Numbers The mass numbers for the isotopes are given as follows: - For \( _{17}^{35}\text{Cl} \), the mass number is 35. - For \( _{17}^{37}\text{Cl} \), the mass number is 37. ### Step 3: Calculate the Number of Neutrons The number of neutrons in an isotope can be calculated using the formula: \[ \text{Number of Neutrons} = \text{Mass Number} - \text{Atomic Number} \] - For \( _{17}^{35}\text{Cl} \): \[ \text{Number of Neutrons} = 35 - 17 = 18 \] - For \( _{17}^{37}\text{Cl} \): \[ \text{Number of Neutrons} = 37 - 17 = 20 \] ### Step 4: Compare the Number of Neutrons Now we can compare the number of neutrons in both isotopes: - \( _{17}^{35}\text{Cl} \) has 18 neutrons. - \( _{17}^{37}\text{Cl} \) has 20 neutrons. ### Conclusion The difference between the two isotopes \( _{17}^{35}\text{Cl} \) and \( _{17}^{37}\text{Cl} \) lies in the number of neutrons. Specifically, \( _{17}^{35}\text{Cl} \) has 18 neutrons, while \( _{17}^{37}\text{Cl} \) has 20 neutrons. Therefore, the difference in the number of neutrons is: \[ 20 - 18 = 2 \] ### Final Answer The difference in \( _{17}^{35}\text{Cl} \) and \( _{17}^{37}\text{Cl} \) is in the number of neutrons, which is 2. ---

To find the difference between the isotopes \( _{17}^{35}\text{Cl} \) and \( _{17}^{37}\text{Cl} \), we can follow these steps: ### Step 1: Identify the Atomic Number The atomic number of chlorine (Cl) is 17. This means both isotopes have the same number of protons. ### Step 2: Identify the Mass Numbers The mass numbers for the isotopes are given as follows: - For \( _{17}^{35}\text{Cl} \), the mass number is 35. ...
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