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NH(4)COONH(2)(s)hArr2NH(3)(g)+CO(2)(g) I...

`NH_(4)COONH_(2)(s)hArr2NH_(3)(g)+CO_(2)(g)` If equilibrium pressure is 3 atm for the above reaction, then `K_(p)` for the reaction is

A

4

B

27

C

`4//27`

D

`1//27`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_(NH_(3)):P_(CO_(2))=2:1`
`thereforeP_(NH_(3))=2atm, P_(CO_(2))=1`
`K_(p)=[P_(NH_(3))]^(2).[P_(CO_(2))]=2^(2)xx1=4`
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