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If alpha is the fraction of HI dissociat...

If `alpha` is the fraction of HI dissociated at equilibrium in the reaction, `2HI(g)hArrH_2(g)+I_2(g)` starting with the 2 moles of HI. Then the total number of moles of reactants and products at equilibrium are

Text Solution

Verified by Experts

The correct Answer is:
2
`2HIhArrH_(2)+I_(2)`
`{:("Initial mole",2,0,0),("At eq.",2(1-alpha),alpha,alpha):}`
Total mole `=2(1-alpha)+alpha+alpha=2`
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