which of the following dissolves in water to give a neutral solution

Options

A. `(NH_(4))_(2)SO_(4)`
B. `Ba(NO_(3))_(2)`
C. `CrCl_(3)`
D. `CuSO_(4)`

Explanation

To determine which of the given salts dissolves in water to give a neutral solution, we need to analyze the acidic and basic components of each salt. A neutral solution is formed when the acidic and basic parts of the salt do not affect the pH of the solution, which typically occurs when both parts are derived from strong acids and strong bases.

### Step-by-Step Solution:

1. **Identify the Salts:**
We have four salts to evaluate. Let's denote them as:
- Option A: Ammonium chloride (NH4Cl)
- Option B: Barium nitrate (Ba(NO3)2)
- Option C: Chromium(III) chloride (CrCl3)
- Option D: Copper(II) sulfate (CuSO4)

2. **Analyze Each Salt:**
- **Option A: Ammonium chloride (NH4Cl)**
- NH4+ comes from ammonia (NH3), which is a weak base.
- Cl- comes from hydrochloric acid (HCl), which is a strong acid.
- Since NH4+ is weak and Cl- is strong, the solution will be acidic.

- **Option B: Barium nitrate (Ba(NO3)2)**
- Ba2+ comes from barium hydroxide (Ba(OH)2), which is a strong base.
- NO3- comes from nitric acid (HNO3), which is a strong acid.
- Both parts are strong, hence the solution will be neutral.

- **Option C: Chromium(III) chloride (CrCl3)**
- Cr3+ comes from chromium hydroxide (Cr(OH)3), which is a weak base.
- Cl- comes from hydrochloric acid (HCl), which is a strong acid.
- Since Cr3+ is weak and Cl- is strong, the solution will be acidic.

- **Option D: Copper(II) sulfate (CuSO4)**
- Cu2+ comes from copper(II) hydroxide (Cu(OH)2), which is a weak base.
- SO4^2- comes from sulfuric acid (H2SO4), which is a strong acid.
- Since Cu2+ is weak and SO4^2- is strong, the solution will be acidic.

3. **Conclusion:**
After analyzing all options, we find that only **Option B: Barium nitrate (Ba(NO3)2)** dissolves in water to give a neutral solution.