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The hydrogen ion concentration in weak a...

The hydrogen ion concentration in weak acid of dissociation constant `K_(a)` and concentration `c` is nearly equal to

A

`sqrt(K_(a)//c)`

B

`c//K_(a)`

C

`K_(a)c`

D

`sqrt(K_(a)c)`

Text Solution

Verified by Experts

The correct Answer is:
D
`{:(HA,rarr,H^(+),+,A^(-)),(C(1-alpha),,C alpha,,C alpha):}`
Hydrogen ion concentration `[H^(+)] = C alpha` ....(i)
By the ostwald's law `alpha = sqrt((K_(a))/(C))` ...(ii)
By putting this value in equation (i) we get
`rArr c xx sqrt((K_(a))/(C)) = sqrt(K_(a)C)`.
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Knowledge Check

  • In pure water hydrogen ion concentration is -

    A
    `10^(-7)`
    B
    `10^(-10)`
    C
    `10^(-2)`
    D
    `10^(-1)`

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    alkaline
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    rainwater
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    a neutral solution

  • The hydrogen ion concentration of a 0.006 M benzoic acid solution is (K_(a) = 6 xx 10^(-5))

    A
    `0.6 xx 10^(-4)`
    B
    `6 xx 10^(-4)`
    C
    `6 xx 10^(-5)`
    D
    `3.6 xx 10^(-4)`

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