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The dissocication constant of a weak aci...

The dissocication constant of a weak acid is `1.0xx10^(-5)`, the equilibrium constant for the reaction with strong base is

A

`1.0 xx 10^(-5)`

B

`1.0 xx 10^(-9)`

C

`1.0 xx 10^(9)`

D

`1.0 xx 10^(14)`

Text Solution

Verified by Experts

The correct Answer is:
C
`HA hArr H^(+) + A^(-) , K_(a) = ([H^(+)][A^(-)])/([HA])` ....(i)
`K = ([A^(-)])/([HA][OH^(-)])` ....(ii)
Dividing (i) by (ii) `(K_(a))/(K) = [H^(+)] [OH^(-)] = K_(w) = 10^(-14)`
`K = (K_(a))/(K_(w)) = (10^(-5))/(10^(-14)) = 10^(9)`
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