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Standard enthalpy of vaporisationDeltaV(...

Standard enthalpy of vaporisation`DeltaV_(vap).H^(Theta)` for water at `100^(@)C`is`40.66kJmol^(-1)`.The internal energy of Vaporization of water at` 100^(@)C("in kJ mol"^(-1))`is

A

`+37.56`

B

`-43.76`

C

`+43.76`

D

`+40.66`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaH=DeltaE+Deltan(g)RT`
`40.66xx1000=DeltaE+(1)xx8.314xx373`
`DeltaE=37.56 kJ mol^(-1)`
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