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As O2 (I) is cooled at 1 atm pressure , ...

As `O_2` (I) is cooled at 1 atm pressure , it freezes to form solid I at 54.5 K. At a lower temperature , solid rearrange to solid II, which has a different crystal that for the phase transition solid to slid II , `DeltaH=-743.1 Jmol^(-1) and DeltaS=-17.0JK^(-1) mol^(-1)` . At what temperature are solids I and II in equilibrium ?

A

2.06 K

B

31.5 K

C

43.7 K

D

53.4 K

Text Solution

Verified by Experts

The correct Answer is:
C
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