The half-life period for the first order reaction is 693 seconds. The rate constant of this reaction would be

Options

A. `0.1 sec^(-1)`
B. `0.01 sec^(-1)`
C. `0.001 sec^(-1)`
D. `0.001 sec^(-1)`

Answer

c

Explanation

`t_(1//2) = (0.693)/(k)` Given `t_(1//2) = 693` sec
`693 = (0.693)/(k) , k = (693 xx 10^(-3))/(693) , k = 10^(-3) = 0.001 sec^(-1)`.