Home
Class 12
CHEMISTRY
The value of rate constant for a f...

The value of rate constant for a first order reaction is 2.303 `xx10^(-2) sec^(-1)` . What will be time required to reduce the concentration to ` (1)/(10)` th of its initial concentration ?

A

10 second

B

100 second

C

2303 second

D

230.3 second

Text Solution

Verified by Experts

The correct Answer is:
b
`t = (2.303)/(K)` log `([A_(0)])/([A])`
`t = (2.303)/(2.303 xx 10^(-2)) "log" (100)/(10) implies t = 10^(2)` log 10 `implies t = 100` sec
Promotional Banner

Similar Questions

Explore conceptually related problems

The rate constant of a first order reaction is 6.9xx10^(-3)s^(-1) . How much time will it take to reduce the initial concentration to its 1//8^("th") value?

At T (K) , if the rate constant of a first order reaction is 4.606xx10^(-3)s^(-1) , the time to reduce the initial concentration of the reactant to (1)/(10) in seconds is :

Rate constant for a reaction is 10^(-3) S^(-1) . How much time is required to reduce the initial concentration of reactant to 25%

The rate constant for a first order reaction is \(50s^{-1}\). How much time it will take to reduce the concentration of the reactant to \(1/10^{ th}\) of its initial value,

The rate constant for the first order reaction is 60 s^(-1) . How much time will it take to reduce the concentration of the reactant to 1//16th value ?