The IUPAC name of the following compound is
`HOOC - CH_(2)-underset(COOH)underset(|)(CH)-CH_(2)-CH_(2)-COOH`

Options

A. 2-(carboxy methyl)-pentane-1, 5-dioic acid
B. 3-carboxy hexane-1, 6 dioic acid
C. Butane , 1, 2, 4, -tricarboxylic acid
D. 4-carboxy hexane-1, 6 dioic acid

Explanation

To determine the IUPAC name of the given compound, we will follow these steps:

### Step 1: Identify the Functional Groups
The compound has three carboxylic acid groups (-COOH). This indicates that we are dealing with a tricarboxylic acid.

**Hint:** Look for the functional groups present in the compound first.

### Step 2: Determine the Longest Carbon Chain
Next, we need to identify the longest continuous carbon chain that can accommodate the functional groups. In this case, we can see that there is a chain of four carbon atoms.

**Hint:** Count the number of carbon atoms in the longest chain that includes the functional groups.

### Step 3: Number the Carbon Chain
We will number the carbon chain to give the carboxylic acid groups the lowest possible numbers. Starting from one end of the chain, we find that the carboxylic acid groups are located at positions 1, 2, and 4.

**Hint:** Always number the carbon chain from the end that gives the functional groups the lowest possible locants.

### Step 4: Write the Base Name
The base name for a four-carbon alkane is "butane". Since we have three carboxylic acid groups, we will use the prefix "tricarboxylic" to indicate their presence.

**Hint:** The base name is derived from the number of carbon atoms in the longest chain.

### Step 5: Combine the Information
Combining all the information, we have:
- The base name is "butane".
- The carboxylic acid groups are located at positions 1, 2, and 4.
- Therefore, the full IUPAC name is "butane-1,2,4-tricarboxylic acid".

**Hint:** When combining the information, ensure that the locants and the functional group prefixes are correctly placed.

### Final Answer
The IUPAC name of the compound is **butane-1,2,4-tricarboxylic acid**.