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The hyperconjugative stabilities of tert...

The hyperconjugative stabilities of tert-butyl cation and `2`-butene, respectively, are due to

A

`sigma rarr p` (empty) and `sigma rarr pi^(**)` electron delocalisations

B

`sigma rarr sigma^(**)` and `sigma - rarr` electron delocalisations

C

`sigma rarr p` (filled) and `sigma rarr pi` electron delocalisations

D

p (filled) `rarr sigma^(**)` and `sigma rarr pi^(**)` electron delocalisations

Text Solution

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The correct Answer is:
A
`{:(" "H,," "H^(o+)),(" |",,),(" "CH_(2),," "CH_(2)),(" |",," ||"),(CH_(3)-C^(o+),,CH_(3)-C),(" |",," |"),(" "CH_(3),," "CH_(3)):}`
In tert-butyl cation, bearing `o+` charge has one vacant p orbital hence it is `sigma`- p (empty) conjugation or Hyperconjugation.

In 2-butene hyperconjugation between `sigma` and `pi^(**)` bond.
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|| Hyperconjugation revision || stability comparison OF alkene and carbocation ||

(A) tert-Butyl methyl ether on cleavage with HI at 373K gives tert-butyl iodide and methanol. (R ) The reaction occurs by S_(N^(2)) mechanism.