`C_(6)H_(5)^(11)COOH` on heating with `Na_(2)CO_(3)` releases

Options

A. `CO_(2)`
B. `.^(14)CO_(2)`
C. `CO`
D. None of these

Explanation

To solve the question regarding the reaction of benzoic acid (C6H5COOH) with sodium carbonate (Na2CO3), we can break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is benzoic acid (C6H5COOH), which is a carboxylic acid.
- The other reactant is sodium carbonate (Na2CO3), which is a basic compound.

2. **Understand the Reaction Type**:
- When a carboxylic acid reacts with a base like sodium carbonate, an acid-base reaction occurs. The carboxylic acid donates a proton (H+) to the base.

3. **Formation of Benzoate Ion**:
- In this reaction, the benzoic acid will lose a proton (H+) and form the benzoate ion (C6H5COO^-). The reaction can be represented as:
\[ C6H5COOH + Na2CO3 \rightarrow C6H5COO^- + Na^+ + H2O + CO2 \]

4. **Release of Carbon Dioxide**:
- Sodium carbonate reacts with the proton from the benzoic acid, leading to the release of carbon dioxide (CO2) gas. This occurs because the carbonate ion (CO3^2-) reacts with the hydrogen ion (H+) to form bicarbonate (HCO3^-), which can further decompose to release CO2:
\[ HCO3^- \rightarrow CO2 + H2O \]

5. **Final Products**:
- The final products of the reaction are carbon dioxide (CO2), water (H2O), and the sodium salt of benzoic acid (sodium benzoate, C6H5COONa). However, since the question specifically asks for what is released, we focus on CO2.

### Conclusion:
The main product released upon heating benzoic acid with sodium carbonate is carbon dioxide (CO2).