The ozonolysis of `gt C= C lt ` produces

Options

A. `gt C=O+O =C lt`
B. `gt C= O =O`
C.
D.

Explanation

To solve the question regarding the ozonolysis of an alkene (represented as C=C), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant in this case is an alkene, which has a carbon-carbon double bond (C=C).

2. **Ozonolysis Reaction**: When an alkene undergoes ozonolysis, it reacts with ozone (O3). This reaction involves the formation of an ozonide intermediate.

3. **Breaking of the Double Bond**: The double bond between the two carbon atoms breaks, leading to the formation of two carbonyl groups. Each carbon atom will now be bonded to an oxygen atom.

4. **Formation of Carbonyl Compounds**: The ozonolysis of the alkene results in the formation of two carbonyl compounds. Specifically, each carbon atom will form a carbonyl group (C=O). Thus, we will have two carbonyl compounds, which can be represented as:
- Carbonyl compound 1: C=O (from one carbon)
- Carbonyl compound 2: C=O (from the other carbon)

5. **Reduction Step**: In the presence of zinc (Zn), the ozonide intermediate can be reduced to yield the final products. The zinc reacts with one of the oxygen atoms to form zinc oxide (ZnO).

6. **Final Products**: The final products of the ozonolysis of the alkene are two carbonyl compounds (aldehydes or ketones depending on the structure of the alkene) and zinc oxide (ZnO).

### Conclusion:
The ozonolysis of the alkene (C=C) produces two carbonyl compounds (C=O) and zinc oxide (ZnO).