`CH_3-C-=CH underset(Zn//H_2O_2) overset(O_3)to` Product . Product in above reaction is

Options

A. `CH_3COOH`
B. `HCOOH`
C. Both (a) and (b)
D. `CH_3CHO+HCHO`

Answer

To solve the question, we need to analyze the reaction involving the compound \( CH_3-C \equiv CH \) (which is propyne) undergoing ozonolysis followed by treatment with zinc and hydrogen peroxide.

### Step-by-Step Solution:

1. **Identify the Compound**: The starting compound is propyne, which can be represented as \( CH_3-C \equiv CH \).

2. **Ozonolysis Reaction**: Ozonolysis is a reaction where an alkene or alkyne is treated with ozone (\( O_3 \)) to form ozonides, which can then be further processed to yield carbonyl compounds (aldehydes or ketones). In this case, propyne will undergo ozonolysis.

3. **Formation of Ozonide**: When propyne reacts with ozone, it forms an ozonide intermediate. The structure of the ozonide will depend on the cleavage of the triple bond.

4. **Reduction of Ozonide**: The ozonide is then treated with zinc (\( Zn \)) and hydrogen peroxide (\( H_2O_2 \)). This step is crucial as it leads to oxidative cleavage of the ozonide.

5. **Products of the Reaction**: The oxidative ozonolysis of propyne will yield two products:
- Acetic acid (\( CH_3COOH \))
- Formic acid (\( HCOOH \))

6. **Conclusion**: Therefore, the final products of the reaction \( CH_3-C \equiv CH \) under the conditions specified (ozonolysis followed by reduction with \( Zn/H_2O_2 \)) are acetic acid and formic acid.

### Final Answer:
The product of the reaction is both acetic acid and formic acid.