Statement 1:Addition of `Br_2` to 1-butene gives two optical isomers.
Statement 2:The product contains one asymmetric carbon

Options

A. Statement 1 is true , statement 2 is true , statement 2 is a correct explanation for statement 1
B. Statement 1 is true , statement 2 is true , statement 2 is not a correct explanation for statement 1
C. Statement 1 is true , statement 2 is false
D. Statement 1 is false , statement 2 is true

Explanation

To analyze the statements regarding the addition of \( Br_2 \) to 1-butene, we can break down the solution step by step.

### Step 1: Understand the Structure of 1-Butene
1-butene is an alkene with the following structure:

```
H H H
| | |
H--C==C--C--C--H
| | |
H H H
```

In this structure, the double bond is between the first and second carbon atoms.

### Step 2: Addition of \( Br_2 \) to 1-Butene
When \( Br_2 \) is added to 1-butene, the reaction occurs via an electrophilic addition mechanism. The double bond opens up, and bromine atoms add across the double bond.

### Step 3: Formation of the Product
The addition of \( Br_2 \) to 1-butene results in the formation of a dibromide. The product can be represented as:

```
Br H H
| | |
H--C--C--C--C--H
| | |
H Br H
```

### Step 4: Identify Asymmetric Carbon
In the product, the second carbon (C2) now has four different groups attached to it (Br, H, CH2, and CH3), making it an asymmetric carbon. This asymmetry allows for the formation of optical isomers (enantiomers).

### Step 5: Conclusion on Statements
- **Statement 1**: The addition of \( Br_2 \) to 1-butene gives two optical isomers. This is **true** because the product has one asymmetric carbon, leading to two enantiomers.
- **Statement 2**: The product contains one asymmetric carbon. This is also **true**.

### Final Answer
Both statements are true, and Statement 2 correctly explains Statement 1.