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Amongest the following the maximum numbe...

Amongest the following the maximum number of alkenes which shows geometrical isomers are 1-pentene, 2-butene, 2-pentene, 1-butene ,propne, 2,3-dimethyl-2-butene, 3-hexene, 1-hexene

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To determine which of the given alkenes can exhibit geometrical isomerism, we need to analyze each compound based on its structure and the presence of a double bond. Geometrical isomerism occurs in alkenes when there are different groups attached to the carbon atoms involved in the double bond. ### Step-by-Step Solution: 1. **Identify the Alkenes:** The alkenes given in the question are: - 1-pentene - 2-butene - 2-pentene - 1-butene - Propene - 2,3-dimethyl-2-butene - 3-hexene - 1-hexene 2. **Draw the Structures:** - **1-pentene (C5H10)**: CH2=CH-CH2-CH2-CH3 - **2-butene (C4H8)**: CH3-CH=CH-CH3 (can be cis or trans) - **2-pentene (C5H10)**: CH3-CH=CH-CH2-CH3 (can be cis or trans) - **1-butene (C4H8)**: CH2=CH-CH2-CH3 - **Propene (C3H6)**: CH2=CH-CH3 - **2,3-dimethyl-2-butene (C6H12)**: (CH3)2C=CH-CH3 (can be cis or trans) - **3-hexene (C6H12)**: CH3-CH2-CH=CH-CH2-CH3 (can be cis or trans) - **1-hexene (C6H12)**: CH2=CH-CH2-CH2-CH2-CH3 3. **Analyze for Geometrical Isomerism:** - **1-pentene**: No geometrical isomers (both carbons in the double bond have identical groups). - **2-butene**: Yes, can have cis and trans isomers. - **2-pentene**: Yes, can have cis and trans isomers. - **1-butene**: No geometrical isomers (both carbons in the double bond have identical groups). - **Propene**: No geometrical isomers (both carbons in the double bond have identical groups). - **2,3-dimethyl-2-butene**: Yes, can have cis and trans isomers. - **3-hexene**: Yes, can have cis and trans isomers. - **1-hexene**: No geometrical isomers (both carbons in the double bond have identical groups). 4. **Count the Alkenes with Geometrical Isomers:** The alkenes that can exhibit geometrical isomerism are: - 2-butene - 2-pentene - 2,3-dimethyl-2-butene - 3-hexene Thus, there are **4 alkenes** that can show geometrical isomers. ### Final Answer: The maximum number of alkenes that show geometrical isomers among the given options is **4**.

To determine which of the given alkenes can exhibit geometrical isomerism, we need to analyze each compound based on its structure and the presence of a double bond. Geometrical isomerism occurs in alkenes when there are different groups attached to the carbon atoms involved in the double bond. ### Step-by-Step Solution: 1. **Identify the Alkenes:** The alkenes given in the question are: - 1-pentene - 2-butene ...
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